p+1,p+3,3p-1 are in AP FIND p
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Given that p+1, p+3, 3p-1 are in A.P.
Thus, difference between terms, 'd' must be equal.
Equating,
(p+3) - (p+1) = (3p-1) - (p+3)
=> 2 = 2p - 4
=> 6 = 2p
=> p = 3.
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