Math, asked by kunal117603, 1 year ago

(p-1/p) (p+1/p) (p²+1/p²) (p⁴+1/p⁴)

Answers

Answered by Shrivastava333

6

Answer:

Step-by-step explanation:

Attachments:

Answered by Anonymous

4

Answer:

Step-by-step explanation:

P6-1/P4

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