Math, asked by shreyamathur6680, 11 months ago

(p - 1/p) (p + 1/p) (p²+ 1/p²) ( p⁴+ 1/p⁴)

Answers

Answered by Saby123
32

Question -

Expand -

 \sf{ ( p - \dfrac{1}{p} ) ( p + \dfrac{1}{p} ) ( p^2 + \dfrac{1}{ p^2 } )( p^4 + \dfrac{1}{ p^4 } ) }

Solution -

 \sf{ ( p - \dfrac{1}{p} ) ( p + \dfrac{1}{p} ) ( p^2 + \dfrac{1}{ p^2 } )( p^4 + \dfrac{1}{ p^4 } ) } \\ \\ \sf{ => ( p^2 - \dfrac{1}{ p^2 } )( p^2 + \dfrac{1}{ p^2 } )( p^4 + \dfrac{1}{ p^4 } ) } \\ \\ \sf{ => ( p^4 - \dfrac{1}{ p^4} )( p^4 + \dfrac{1}{ p^4 } ) } \\ \\ \sf{ => (p^8 - \dfrac{1}{ p^8 } ) } \\ \\ \sf{ \bold{ Hence \: Expanded } }

Additional Identities -

 \sf{ (a - b )( a + b ) = a^2 - b^2 } \\ \\ \sf{ ( a + b )^2 = a^2 + 2ab + b^2 } \\ \\ \sf{ ( a - b )^2 = a^2 - 2ab + b^2 }

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