Question

p= -10/13, q= 1/26 and r = -1/-2, then verify that p+ (q+r) = (p+q) + r

Answer 1

Step-by-step explanation:

To prove

p+(q+r) = (p+q)+r,

LHS,

p+(q+r)

$\frac{- 10}{13} + ( \frac{1}{26} + \frac{1}{2} )$

$\frac{- 10}{13} + ( \frac{1 + 13}{26} )$

$\frac{ - 10}{13} + \frac{14}{26}$

$\frac{ - 10}{13} + \frac{7}{13}$

$\frac{ - 3}{13}$

similary,

RHS (p+q)+r

$( \frac{- 10}{13} +\frac{1}{26}) + \frac{1}{2} )$

$( \frac{ -20 + 1}{26} ) + \frac{1}{2}$

$\frac{ - 19}{26} + \frac{1}{2}$

$\frac{ - 19 + 13}{26}$

$\frac{ - 6}{26}$

$\frac{ - 3}{13}$

Lhs=Rhs proved

hope it helped you ;)