Question

p=₹10000,i=₹2500,r=₹0.125℅ s.i the no of year t will be​

Answer 1

$simple \: intrest = \frac{p \times r \times t}{100}$

P = Principal (In Rupees)

r = rate of intrest (In % )

t = time period (In years)

GIVEN :-

S.I. = Rs.2500

r = 12.5%

p = Rs.10000

t = ? yrs

SOLUTION :-

$SI = \frac{r \times t \times p}{100} \\ \\ \implies2500 = \frac{ \frac{125}{10} \times t \times 10000}{100} \\ \\ \implies2500 = 125 \times 10 \times t \\ \\ \implies t = \frac{2500}{1250} \\ \\ \implies t = 2$

The number of year will be 2yrs