Question

P=10000,R=5% find the amount in 6 years compounded for every two years

Answer 1

Check this out,

$a = p {(1 + \frac{r}{100} )}^{ \frac{6}{2} } \\ a = 10000 {(1 + \frac{5}{100}) }^{3} \\ a = 10000 {( \frac{105}{100}) }^{3} \\ a = 10000 \times \frac{ {105}^{3} }{ {100}^{3} } \\ a = 10000 \times \frac{ {105}^{3} }{1000000} \\ a = \frac{ {105}^{3} }{100} \\ a = \frac{{(100 + 5)}^{3} }{100} \\ a = \frac{1000000 + 25 + (1500 \times 105)}{100} \\ a = \frac{1000000 + 25 + 157500}{100} \\ a = \frac{1157525}{100} \\ a = 11575.25$

Here is your answer
Plz Mark it as brainliest answer.
and drop a ❤

Answer 2

Answer:

It answer is rupees 13310