P=12000,years=3,Rate of interest=10℅ find C.I
Answers
Answered by
0
Answer:
Answer:
Compound interest = Rs.3972
Explanation:
We know,
→ C.I. = Amount - principal
Using amount formula,
\implies \rm \: A = p \bigg(1 + \dfrac{r}{100} \bigg)^{n}⟹A=p(1+
100
r
)
n
Where,
p(principal) = Rs.12,000
r(rate) = 10% p.a.
n(time) = 3 yrs.
Substitute the given values,
\rm = 12000\bigg(1 + \dfrac{10}{100} \bigg)^{3}=12000(1+
100
10
)
3
\rm = 12000\bigg(1 + \dfrac{1}{10} \bigg)^{3}=12000(1+
10
1
)
3
\rm = 12000\bigg( \dfrac{11}{10} \bigg)^{3}=12000(
10
11
)
3
\rm = 12000 \times \dfrac{1331}{1000}=12000×
1000
1331
\rm = 12 \times 1331=12×1331
= 15972=15972
∴ Compund interest :-
CI=3600
Similar questions