P 13. Given : sin 0 = p/q find cos 0 + sin in terms of p and q.
Answers
Answer:
Correct option is
C
q
p+
q
2
−p
2
Given, sinΘ=
q
p
sinΘ=
H
P
=
q
p
Now, by Pythagoras Theorem,
H
2
=P
2
+B
2
q
2
=p
2
+B
2
B=
q
2
−p
2
sinΘ+cosΘ=
H
P
+
H
B
=
q
p
+
q
q
2
−p
2
=
q
p+
q
2
−p
2
Step-by-step explanation:
please make as thanks
Step-by-step explanation:
Let the angle be x instead of theta
Given sin x = p / q
We know that sin x = opposite side / hypotenuse
So p = opposite side
q = hypotenuse
We also know from Pythagoras theorem,
Hypotenuse² = Opposite side ² + Adjacent side ²
Let the adjacent side be y
then
q² = p² + y²
q² - p² = y²
So now cos x + sin x = adjacent side + opposite side
Hypotenuse Hypotenuse
= y + p
q
= sqrt ( q² - p²) + p
q
= sqrt [( q + p ) ( q- p ) ] + p
q