Math, asked by dashsiprasanghamitra, 9 hours ago

P 13. Given : sin 0 = p/q find cos 0 + sin in terms of p and q.​

Answers

Answered by nikhilrajgone2008
3

Answer:

Correct option is

C

q

p+

q

2

−p

2

Given, sinΘ=

q

p

sinΘ=

H

P

=

q

p

Now, by Pythagoras Theorem,

H

2

=P

2

+B

2

q

2

=p

2

+B

2

B=

q

2

−p

2

sinΘ+cosΘ=

H

P

+

H

B

=

q

p

+

q

q

2

−p

2

=

q

p+

q

2

−p

2

Step-by-step explanation:

please make as thanks

Answered by meghananadella
0

Step-by-step explanation:

Let the angle be x instead of theta

Given sin x = p / q

We know that sin x = opposite side / hypotenuse

So p = opposite side

q = hypotenuse

We also know from Pythagoras theorem,

Hypotenuse² = Opposite side ² + Adjacent side ²

Let the adjacent side be y

then

q² = p² + y²

q² - p² = y²

So now cos x + sin x = adjacent side + opposite side

Hypotenuse Hypotenuse

= y + p

q

= sqrt ( q² - p²) + p

q

= sqrt [( q + p ) ( q- p ) ] + p

q

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