Physics, asked by Toto3sumi, 11 months ago

P^2 + 1/P^2= 11 ,find the value of p-1/p

Answers

Answered by Anonymous
1

Explanation:

p^2 + 1/p^2 = 11

(p - 1/p)^2 + 2(p)(1/p) = 11

(p - 1/p)^2 + 2 = 11

(p - 1/p)^2 = 11 - 2

(p - 1/p)^2 = 9

p - 1/p = ±√9

p - 1/p = ± 3

Answered by Anonymous
6

HEYA \:  \\  \\ GIVEN \:  \: QUESTION \: Is \:  \:  \\  \\  p {}^{2}  +  \frac{1}{p {}^{2} }  = 11 \:  \:  \:  \:  \:  \: find \:  \: p -  \frac{1}{p}  \\  \\ let \:  \:  \:  \: p -  \frac{1}{p}  = z \\ squaring \: on \: both \: sides \: w e \: have \\  \\ (p -  \frac{1}{p} ) {}^{2}  = z {}^{2}  \\  \\ p {}^{2}  +  \frac{1}{p {}^{2} }  -  \frac{2p}{p}  = z {}^{2}  \\  \\ 11 - 2 = z {}^{2}  \\  \\ z {}^{2}  = 9 \\  \\ z =  \sqrt{9}  \:  \:  \: or \:  \:  \: z =  -  \sqrt{9}  \\  \\ z = 3 \:  \:  \: or \:  \:  \: z =  - 3 \\  \\ therefore \:  \:  \:  \: p -  \frac{1}{p}  = 3 \:  \: or \:  \:  \: p -  \frac{1}{p}  =  - 3

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