Math, asked by envykrisnasarkar08, 9 months ago

{(p^2 - 1/q^2)^p (p-1/q)^q-p} / {(q^2 - 1/p^2)^q (q-1/p)^p-q}

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Answered by Anonymous
1

Answer:

Michael Johnson, Varmo Vene · 2006 · Computers

(P4 Q); R = P + (Q: R) P+ Q = Q3 P P+ emp & P (P. V.P.) + Q = (P + Q) V (P + Q) (P. A P2) + ... in Cforall: {(p1 = n.1, p.2/\x -: n, t) + p2 – n2, q ^ p = p1/\x = z} {(x --, - + ...

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