Question

(p^2-2pq+q^2)-r^2 find the factorise the expressions​

Answer 1

Solution :

(p²-2pq+q²)-r²

= ( p - q )² - r²

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We know the algebraic identity:

( x² - y² ) = ( x + y )( x - y )

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= ( p - q + r )( p - q - r )

Answer 2

Answer:

Step-by-step explanation:

$since\\ (a-b)^{2}a^{2}+b^{2}-2ab\\a^{2}-b^{2}=(a-b)(a+b) \\(p^{2}-2pq+r^{2})-r^{2}\\=(p-q)^{2}-r^{2}\\=(p-q-r)(p-q+r)$

HOPE IT HELPS