Question

p^2 + 2pqxy + x^2y^2. factorize ​

Answer 1

We need to factorise (p

2

−2pq+q

2

)−r

2

We have (p

2

−2pq+q

2

)−r

2

=(p−q)

2

−r

2

By using (a

2

−b

2

)=(a−b)(a+b)

Here a=(p−q),b=r

Therefore, (p

2

−2pq+q

2

)−r

2

=(p−q−r)(p−q+r)

Hence, factors are (p−q−r)(p−q+r).