Question

p^2 +2yp cotx=y^2 find quadratic equation ​

Answer 1

Step-by-step explanation:

The given equation is p2 + 2py cot x = y2 ...(i) (p + y cot x)2 = y2(1 + cot2x) (p + y cot x)2 = y2cosec2 x (p + y cot x) = ± y cosec x p = y(cosec x – cot x) ...(ii) and p = – y(cosec x – cot x) ...(iii) From Eq. (ii), we get, dy/dx = y(cosec x – cot x) dy/y = (cosec x – cot x)dx dy/y = ((1 – cos x)/sin x)dx dy/y = tan(x/2) dx Integrating, we get Read more on Sarthaks.com - https://www.sarthaks.com/563834/solve-p-2-2py-cot-x-y-2

Answer 2

Answer:

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