Question

p^2-34p+64 zeroes of the polynomials...

Answer 1

hey mate here is ur answer

p^2-32p-2p+64=0

p(p-32)-2(p-32)=0

(p-32)(p-2)=0

p=32 or 2.

hope it helps.

Answer 2

Step-by-step explanation:

${p}^{2} - 34p + 64 = 0 \\ = > {p }^{2} - 32p - 2p + 64 = 0 \\ = > p(p - 32) - 2(p - 32) = 0 \\ = > (p - 2)(p - 32) = 0 \\ = > p = 2 \: or \: 32$