Question

p(-2,5) and Q(3,2) are the points .find the co-irdinates of the point R on PQ ​

Answer 1

Where is point R? Position?

Step-by-step explanation:

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Answer 2

R (x,y) = under root (x2-x1)^2 + (y2-y1)^2
= under root (3- -2)^2. + (2-5)^2
=under root 5^2 + (-3)^2
=under root 25+9
=under root 34
Therefore answer is root 34



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