P(-2,-5), Q(4,3), a:b=3:4 find the co-ordinates of point A which divides segment PQ in the ratio a:b.
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Given,
Co-ordinates of the Point P (x₁, y₁) = (-2,-5)
Co-ordinates of the Point Q (x₂, y₂) = (4, 3)
Ration of division ( m₁:m₂) = 3 : 4
Now, Using the Section Formula,
A(x,y) = [(m₁x₂ + m₂x₁)/(m₁ + m₂) , (m₁y₂ + m₂y₁)/(m₁ + m₂)]
= [( 3 × 4 + 4 × -2 )/(3 + 4) , (3 × 3 + 4 × -5 )/(3 + 4)]
= [4/7 , -11/7]
= (4/7,-11/7)
Hence, the co-ordinates of the Point A is (4/7, -11/7).
Hope it helps.
Co-ordinates of the Point P (x₁, y₁) = (-2,-5)
Co-ordinates of the Point Q (x₂, y₂) = (4, 3)
Ration of division ( m₁:m₂) = 3 : 4
Now, Using the Section Formula,
A(x,y) = [(m₁x₂ + m₂x₁)/(m₁ + m₂) , (m₁y₂ + m₂y₁)/(m₁ + m₂)]
= [( 3 × 4 + 4 × -2 )/(3 + 4) , (3 × 3 + 4 × -5 )/(3 + 4)]
= [4/7 , -11/7]
= (4/7,-11/7)
Hence, the co-ordinates of the Point A is (4/7, -11/7).
Hope it helps.
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