Math, asked by arvind65, 1 year ago

p = ( 2-a), what is the value of a^3 + 6ap + p^3 - 8

Answers

Answered by RAPTOR5
1
0. PUT value of p. as 2-a
a^3+6a(2-a)+(2-a)^3-8
a^3 +6a(2-a) +8 -a^3 -6a(2-a)
=0

hope it helps.
Similar questions