Question

p^2 - p -118 = 0 what is the solution​

Answer 1

${\huge{\gray{\underline{\mathbb{\red{Ans}{\orange{wer}{\blue{:-} }}}}}}}$

${p}^{2} - p - 118$

$a = 1 \\ b = - 1 \\ c = - 118$

$d = {b}^{2} - 4ac \\ d = 1 + 472 \\ d = 473$

$p = \frac{ - b + - \sqrt{d} }{2a} \\ p = \frac{1 + - \sqrt{473} }{2}$

$p = \frac{1 + \sqrt{473} }{2}$

$and$

$p = \frac{1 - \sqrt{473} }{2}$