Math, asked by manjumitv, 1 day ago

[p/2+p/3][2p/5-p][3p-2p/3​

Answers

Answered by IIGoLDGrAcEII
4

Answer:

(p + p/3) (2p + (p/2)) (3p – (2p/3))

= p (1 + (1/3)) p(2 + (1/2)) p(3 – (2//3))

=p3 ((3 + 1)/3) ((4 + 1)/2) ((9 – 2)/3)

= p3 × 4/3 × 5/2 × 7/3 = p3 × 70/9 = 70p3/9

Answered by itzmecutejennei
4

Answer:

(p + p/3) (2p + (p/2)) (3p – (2p/3))

= p (1 + (1/3)) p(2 + (1/2)) p(3 – (2//3))

=p3 ((3 + 1)/3) ((4 + 1)/2) ((9 – 2)/3)

= p3 × 4/3 × 5/2 × 7/3 = p3 × 70/9 = 70p3/9

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