Question

p^2-p-42 by p+6 divided using factor method​

Answer 1

Answer:

0

Step-by-step explanation:

p(-6)= $(-6)^{2}$-(-6)-42

       =36+6-42

       = 0

since p(-6) = 0

P(a) is a factor of p+6

Answer 2

Answer:

(p-7)

Step-by-step explanation:

Here ac= 1 times (-42) = -42

And -42 = (-7) times 6

And -7 + 6 = -1

Factorising,

$p^{2}-p-42\\=p^{2}-7p+6p-42\\=p(p-7)+6(p-7)\\=(p-7)(p+6)$

So,

$\frac{(p^{2}-p-42)}{(p+6)}=\frac{(p-7)(p+6)}{(p+6)}$

Cancelling (p+6) leaves

(p-7)