Question

p^2+q^2=41 and pq=20 find the value of (p-q)​

Answer 1

Step-by-step explanation:

The value of p^2+q^2p2+q2 is 100.

Step-by-step explanation:

Given information: p + q = 12 and pq = 22.

Using algebraic property:

(p+q)^2=p^2+2pq+q^2(p+q)2=p2+2pq+q2

(12)^2=p^2+2(22)+q^2(12)2=p2+2(22)+q2

144=p^2+44+q^2144=p2+44+q2

144-44=p^2+q^2144−44=p2+q2

100=p^2+q^2100=p2+q2

Therefore the value of p^2+q^2p2+q2 is 100