Question

p^2(q-r)-q(r-q) factorise​

Answer 1

Step-by-step explanation:

Given :-

p^2(q-r)-q(r-q)

To find:-

Factorise p^2(q-r)-q(r-q) ?

Solution:-

Given expression is p^2(q-r)-q(r-q)

It can be written as

=> p^2(q) -p^2(r) -q(r) -q(-q)

=> p^2q -p^2r -qr +q^2

It can be arranged as

=>( p^2q +q^2) - (p^2r+qr)

=> q ( p^2 +q ) - r ( p^2 + q )

=> (p^2 + q) ( q-r)

p^2(q-r)-q(r-q) = (p^2 + q) ( q-r)

Answer:-

The factorization of the given expression p^2(q-r)-q(r-q) is (p^2 + q) ( q-r)

Used Concept:-

• Arranging the given terms by Commutative property.

• Expressing the given expression as the product of factors is called factorization and expressing as the product of prime factors is called Prime factorization.