Math, asked by mahtosagar7261, 4 days ago

p= ₹ 2000 ; r = 10 percentage pa ;n = 3years​

Answers

Answered by swarajshinde124
1

=> C.I = P(1+R/100)^n

=> C.I = 2000(1+10/100)^3

=> C.I = 2000(110/100)^3

=> C.I = 2000 x 110/100 x 110/100 x

KB/S

60

=> C.I = Rs (2000 x 11/10 x 11/10 x 11/10)

=> C.I = Rs (2 x 11 x 11 x 11)

=> C.I = Rs 2662

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