Question

p 24000 T 3 R 785 find tha compound intrest​

Answer 1

Answer:

Principal (P) = Rs.24000

Time (T) = 3 years

Rate of interest (R) = 5 %

As we know that

→ A = P(1 + R/100)ⁿ

→ A = 24000(1 + 5/100)³

→ A = 24000(1 + 1/20)³

→ A = 24000(20 + 1/20)³

→ A = 24000 × 21/20 × 21/20 × 21/20

→ A = 1200 × 21 × 21/20 × 21/20

→ A = 60 × 21 × 21 × 21/20

→ A = 3 × 21 × 21 × 21

→ A = Rs.27,783

Hence,

Amount = Rs.27783

Now,

→ Compound Interest = Amount - Principal

→ C.I = 27783 - 27000

→ C.I = Rs.783

Answer 2

Answer:

CI=136497.87

Step-by-step explanation:

p=24000                              P=24000

R=78.5%,                              R=7.85%

T=3 years                             T=3 years  

Here,                                      Here,

CI=p(1+R/100%)^3                   CI=p(1+R/100%)^3      

   =24000(1+78.5/100)^3          =24000(1+7.85/100)^

    =24000*5.687411625           =24000* 1.254470487  

  CI=136497.87                        CI =30107.29168