Question

p-(2p+5)-5(1-2p)=2(3+4p)-3(p-4)​

Answer 1

Answer:

$p = 7$

Step-by-step explanation:

$=p-(2p+5)-5(1-2p)=2(3+4p)-3(p-4)$

$=p-2p-5-5\left(1-2p\right)=2\left(3+4p\right)-3\left(p-4\right)$

$=-p-5-5\left(1-2p\right)=2\left(3+4p\right)-3\left(p-4\right)$

$=-p-5-5+10p=2\left(3+4p\right)-3\left(p-4\right)$

$=-p-10+10p=2\left(3+4p\right)-3\left(p-4\right)$

$=9p-10=2\left(3+4p\right)-3\left(p-4\right)$

$=9p-10=6+8p-3\left(p-4\right)$

$=9p-10=6+8p-3p+12$

$=9p-10=6+5p+12$

$=9p-10=18+5p$

$=9p-10-5p=18$

$=4p-10=18$

$=4p = 18 + 10$

$=4p = 28$

$=p = \frac{28}{4}$

$=p = 7$

Answer 2

Here is answer

$\big\langle\Big\langle\bigg\langle\Bigg\langle \LARGE\;\underbrace{\underline{\sf{Solving\ the\ equation\big\rangle\Big\rangle\bigg\rangle\Bigg\rangle\\}}}$

p-2p-5-5+10p=6+8p-3p+12

11p-2p-10=18+5p

9p-5p=28

4p=28

p=7

Hope you will find this great