Question

p+2q+3r=0 show that p3+8q3+27r3=18pqr​

Answer 1

Step-by-step explanation:

p+2q+3r=0

(if a+b+c=0 then a^3 + b^3 +c^3=3abc)

p+2q+3r=0

$p ^{3} + 8q ^{3} + 27r {}^{3} = 3p(2q)(3r)$

$p {}^{3} + 8q {}^{3} + 27r {}^{3} = 18pqr$