Question

P= 2t^2+t-5 find dp/dt at t=-1​

Answer 1

Answer:

-3

Explanation:

$\frac{d}{dt}(ax^b)=abx^{b-1}$

$\frac{dP}{dt}=4t+1$

$t=-1$

$=>\frac{dP}{dt}=4(-1)+1=-3$