Question

P(3,1) , Q(6,5) , CR(x,y) are three points such that angle PQR is the right angle and the area of triangle ABC is 7 .?

Answer 1

here's your answer ⏩⏩

$<b>Given,</b>$

$P(x_{1},y_{1}) \: = (3,1) \\ Q(x_{2},y_{2}=(6,5) \\ R(x_{3},y_{3})=(x,y)$

follow the first attachment ⏫⏫

Answer 2

Answer:

Step-by-step explanation:

as we know the formula of area of triangle

A= mod of [a1(b2-c2)+b1(c2-a2)+c1(a2-b2)]/2

=mod of [3(5-y)+6(y-1)+x(1-5)]/2

7 =mod of [15-3y+6y-6+x-5x]/2

14 = mod of [3y-4x+9] -------1

as triangle is right angle then formula

A= (a1b2+b2c3+b3a1-a1c3-b2a1-c1b2)/2

7=(3*5+5*y+y*3-3*y-5*3-x*5)/2

7=(15+5y+3y-3y-15-5x)/2

14=5y-5x ------------2

by solvig eq 1 and 2

x= -17/5

y=31/5