Question

P (3,2) and Q(7,7) are two ponits . Perpendiculars are drawn to the X axis frpm P and Q meeting the X axis at L and M respectively.
i) find the coordinates of L and M
ii)find the lengths LM

Answer 1

Answer:

i)the y coordinate of a point on x-axis is 0.

so, the point L is (3,0)

similarly,the point M is (7,0)

ii)length of LM is:

|x2 - x1|  

where x2=7 and x1=3

so, length=|7-3|=|4|=4

I hope it may help you ^.^

Answer 2

(i.) Therefore the coordinates of L and M are ( 3,0 ) and ( 7,0 ).

(ii.) Therefore the length of LM is 4 units.

Given:

Two points: P(3,2) and Q(7,7)

Perpendiculars are drawn to the x-axis from P and Q meeting at L and  M respectively.

To Find:

(i.) Find the coordinates of L and M

(ii.) Find the lengths LM

Solution:

The given question can be solved as shown below.

Given points: P(3,2) and Q(7,7)

When a line perpendicular to the x-axis is drawn it is parallel to the y-axis. So the x-coordinate remains the same and the y-coordinate changes.

As the points 'L' and 'M' lie on the x-axis their y-coordinate is zero.

So the points become,

⇒ L → ( 3,0 )

⇒ M → ( 7,0 )

(i.) Therefore the coordinates of L and M are ( 3,0 ) and ( 7,0 ).

The length of the line LM is given by,

LM = √( 7-3 )² + ( 0-0 )² = 4 units

(ii.) Therefore the length of LM is 4 units.

(i.) Therefore the coordinates of L and M are ( 3,0 ) and ( 7,0 ).

(ii.) Therefore the length of LM is 4 units.

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