Question

P.
3) In figure, Q=90°,
R=0, PQ=12,
QR = 5, PR = 13.
Find the value of :
cos Ꮎ .​

Answer 1

Step-by-step explanation:

i. PQ = 12, QR = 5 [Given]

In ∆PQR, ∠Q = 90° [Given]

∴ PQ^2= QR2 + PQ2 [Pythagoras theorem] = 25 + 144 ∴ PR^2= 169

∴ PR = 13 units [Taking square root of both sides] ii. In right angled ∆PQR, seg QS is the median on hypotenuse PR.

∴ QS = (1/2) PR [In a right angled triangle, the length of the median on the hypotenuse is half the length of the hypotenuse]

= (1/2) x 13

∴ l(QS) = 6.5 units.

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Answer 2

Step-by-step explanation:

cos Ꮎ = (5 / 13) (Ans.)answer