p/3+p/4=55-p+40/5 Solve the above problem please
Answers
Step-by-step explanation:
Given Equation is \frac{p}{3} + \frac{p}{4} = 55 - p + \frac{40}{5}
3
p
+
4
p
=55−p+
5
40
\frac{p}{3} + \frac{p}{4} = 55 - p + 8
3
p
+
4
p
=55−p+8
\frac{p}{3} + \frac{p}{4} = - p+63
3
p
+
4
p
=−p+63
\frac{p}{3} + \frac{p}{4} + p = 63
3
p
+
4
p
+p=63
\frac{4p + 3p + 12p}{12} = 63
12
4p+3p+12p
=63
\frac{19p}{12} = 63
12
19p
=63
19p = 12 * 63
19p = 756
p = \frac{756}{19}p=
19
756
p = 39.78.
Let the string has T tension, and acceleration is (a
x
i
^
+a
y
j
^
)
μ= friction coefficient
By force equation:
T=Ma
x
-----eq.1
mg−T−Tμ=ma
y
-----eq.2
equation of the string:
y - x = L
by taking differential of both side:
dt
dy
−
dt
dx
=0
dt
2
d
2
y
−
dt
2
d
2
x
=0
a
y
−a
x
=0
a
x
=a
y
-----eq.3
From eq.1 and eq.2
mg−Ma
x
−Ma
x
μ=ma
y
Form eq.3
mg−Ma
x
−Ma
x
μ=ma
x
ma
x
+Ma
x
+Ma
x
μ=mg
a
x
=
m+M+Mμ
mg
acceleration = (
m+M+Mμ
mg
)
i
^
+(
m+M+Mμ
mg
)
j
^