Question

(p-3)x^2+6x+9=0 find the value of p

Answer 1

Question:-

$(p - 3) {x}^{2} + 6x + 9 = 0$

Find the value of p

Solution:-

Given,

$(p - 3) {x}^{2} + 6x + 9 = 0$

Solve by transporting

$(p - 3) = \frac{0}{ {x}^{2} + 6x + 9 }$

$(p - 3) = 0$

$p = + 3$

Final Answer:-

The value of p is 3