Question

p(3x-2)=2x²-3x+5 then p(7)=?​

Answer 1

Answer:

14

Step-by-step explanation:

firstly put 3x-2= 7

3x=7+2

x=3

now find p(3)

i.e.= p(x)=

$2({3}^{2}) - 3 \times 3 + 5$

=2×9-9+5

=18-9+5

=14

Answer 2

Answer:

P(7)=670

Step-by-step explanation:

P(3x-2)=2x²-3x+5

(Substitute (3x-2) in the place of x)

= 2(3x-2)²-3(3x-2)+5

[(3x-2)²=>(a-b)²=a²+b²-2ab]

=2(9x²+4-12x)-(9x-6)+5

=18x²-24x+8-9x+6+5

=18x²-33x+19------------(1)

On To The Question

P(7)=?

[Substitute 7 in place of x in (1)]

P(7)=18(7)²-33(7)+19

=18(49)-231+19

=882-231+19

P(7)=670