Question

P=3x² —6x+7
Q=2x—8x²+6
R=7+5x²—3x
find P+Q— R
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Answer 1

Step-by-step explanation:

P+Q-R

=(3x^2-6x+7)+(2x-8x^2+6)-(7+5x^2-3x)

=3x^2-6x+7+2x-8x^2+6-7-5x^2+3x

=-10x^2-x+6

Answer 2

Answer:

-10x² - x + 6

Step-by-step explanation:

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Given,

P=3x²- 6x + 7

Q=2x - 8x² + 6

R=7 + 5x² - 3x

So,

P+Q-R = (3x²- 6x + 7 ) + (2x - 8x² + 6 ) - (7 + 5x² - 3x)

           = x²(3-8-5) + x(-6+2+3) + (7+6-7)

           = -10x² - x + 6