Question

Зp^ 4- 36р^2 + 108 pls answer this dont spam
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Answer 1

Answer:

(3p² - 18) (p² - 6)

Step-by-step explanation:

3p⁴ - 36p² + 108

= 3p⁴ - 18p² - 18p² + 108

= 3p²(p² - 6) -18(p² - 6)

= (3p² - 18) (p² - 6)

HOPE IT HELPS YOU.

THANKS !

Answer 2

given:-

equation = 3p⁴-36p²+108

solution:-

let's factorise the given equation by splitting the middle term.

===> we will take p⁴=x²

thus, p²=x...................(1)

===> $\tt 3x^2 - 36x + 108$

===> $\tt 3x^2-36x+108$.............(2)

divide the equation (2) by 3

===> $\tt \dfrac{3x^2-36x+108}{3}$

===> $\tt \dfrac{\cancel 3 (x^2-12x+36)}{\cancel 3}$

===> $\tt x^2 - 12x + 36$

===> $\tt x^2 - 6x -6x+36$

===> $\tt x(x-6) -6(x-6)$

===> $\tt (x-6)(x-6)$

===> $\boxed{\tt (x-6)^2 }$

===> $\tt x-6=0$

===> $\tt x=6$

===> $\tt x^2 = p^4$

===> $\tt ✓6 \:is\: the \:value\: of\: p$

hope this helps!!!