Question

(P-4)[(P-2)(P+6)]=5P+3​

Answer 1

Step-by-step explanation:

(P-4)[(P-2)(P+6)]=5P+3

(P-4) (P^2+6P-2P-6)=5P+3

(P-4)(P^2+4P-6)=5P+3

(P^3+4P^2-6P-4P^2-16P+24)=5P+3

(P^3-6P-16P+24)=5P+3

(P^3-22P+24)=5P+3

(P^3-22P-5P)=3-24

(P^3-27P)=-21

(P^3-P)=-21/27

(P^3-P)= - 7/9

Please mark my answer as the brainliest!!

Answer 2

Step-by-step explanation:

LHS=

(P-4) [ (P-2) ( P+6)]

= (P-4)[ P²+6P-2P-12]

= (P-4) ( P²+4P-12)

= P³+4P²-12P-4P²-16P+48

= P³-28P+48

therefore

LHS≠ RHS