p^4-(q+r)^4 factorise the following expression
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I hope this is what you're talking about,
![{p}^{4} - {(q + r)}^{4} \\ \\ = ( {p}^{2} + {(q + r)}^{2}) ( {p}^{2} - {(q + r)}^{2} ) \\ \\ = ( {p}^{2} + {(q + r)}^{2})(p + (q + r))(p - (q + r)) {p}^{4} - {(q + r)}^{4} \\ \\ = ( {p}^{2} + {(q + r)}^{2}) ( {p}^{2} - {(q + r)}^{2} ) \\ \\ = ( {p}^{2} + {(q + r)}^{2})(p + (q + r))(p - (q + r))](https://tex.z-dn.net/?f=+%7Bp%7D%5E%7B4%7D++-++%7B%28q+%2B+r%29%7D%5E%7B4%7D++%5C%5C++%5C%5C+%3D+%28+%7Bp%7D%5E%7B2%7D+%2B++%7B%28q+%2B+r%29%7D%5E%7B2%7D%29++%28++%7Bp%7D%5E%7B2%7D++-++%7B%28q+%2B+r%29%7D%5E%7B2%7D+%29+%5C%5C++%5C%5C++%3D+%28+%7Bp%7D%5E%7B2%7D+%2B++%7B%28q+%2B+r%29%7D%5E%7B2%7D%29%28p++%2B+%28q+%2B+r%29%29%28p+-+%28q+%2B+r%29%29)
And we're done
And we're done
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