p=40/000 r=3% n=2years
Answers
Answer:
Compute the amount and the compound interest in each of the following by using the formulae when:
(i) Principal = Rs 3000, Rate = 5%, Time = 2 years
(ii) Principal = Rs 3000, Rate = 18%, Time = 2 years
(iii) Principal = Rs 5000, Rate = 10 paise per rupee per annum, Time = 2 years
(iv) Principal = Rs 2000, Rate = 4 paise per rupee per annum, Time = 3 years
(v) Principal = Rs 12800, Rate = 712%, Time = 3 years
(vi) Principal = Rs 10000, Rate 20% per annum compounded half-yearly, Time = 2 years
(vii) Principal = Rs 160000, Rate = 10 paise per rupee per annum compounded half-yearly, Time = 2 years.
ANSWER:
Applying the rule A=P(1+R100)n on the given situations, we get:(i)A=3,000(1+5100)2=3,000(1.05)2=Rs 3,307.50Now,CI=A−P=Rs 3,307.50−Rs 3,000=Rs 307.50(ii)A=3,000(1+18100)2=3,000(1.18)2=Rs 4,177.20Now,CI=A−P=Rs 4,177.20−Rs 3,000=Rs 1,177.20(iii)A=5,000(1+10100)2=5,000(1.10)2=Rs 6,050Now,CI=A−P=Rs 6,050−Rs 5,000=Rs 1,050(iv)A=2,000(1+4100)3=2,000(1.04)3=Rs 2,249.68Now,CI=A−P=Rs 2,249.68−Rs 2,000=Rs 249.68(v)A=12,800(1+7.5100)3=12,800(1.075)3=Rs 15,901.40Now,CI=A−P=Rs 15,901.40−Rs 12,800=Rs 3,101.40(vi)A=10,000(1+20200)4=10,000(1.1)4=Rs 14,641Now,CI=A−P=Rs 14,641−Rs 10,000=Rs 4,641(vii)A=16,000(1+10200)4=16,000(1.05)4=Rs 19,448.1Now,CI=A−P=Rs 19,448.1−Rs 16,000=Rs 3,448.1
Step-by-step explanation:
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