Question

P(5, 5) is a point inside the circle x2 + y2 - 4x - 6y - 12 = 0. If the origin is
translated to a certain point and the transformed equation is x2 + y2 = 25,
then the new point P =​

Answer 1

here's your solution bro!

Answer 2

Sifted position of the point P will be at (3,2).

Step-by-step explanation:

The center of the circle with the equation, x² + y² - 4x - 6y - 12 = 0 is given by (2,3) and the radius will be $\sqrt{2^{2} + 3^{2} + 12} = 5$ units.

Now, the circle equation is changed to, x² + y² = 25, and the center of the circle is at (0,0) and the radius is 5 units.

Therefore, the original circle is sifted to 2 units left and 3 units down.

Now, a point P(5,5) is placed inside the original circle and after sifting the new position of the point P will be (5 - 2, 5 - 3) = (3,2). (Answer)