Question

P (-5,7); Q (-1,3) Find distance between points P and Q​

Answer 1

Answer:

4√2

Step-by-step explanation:

d(P,Q)= √(−5−(−1)) ² +(7−3)²

d(P,Q)= √16+16

d(P,Q)= √32

∴d(P,Q)=4√2

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Answer 2

PQ = √(x2-x1)^2+(y2-y1)^2

=√(-1+5)2+(3-7)2

= √4^2+(-4)^2

=√16+16

=√32

=4√2

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