Question

(p-5) (p+3)=0. find root of the quadratic equation​

Answer 1

Answer:

p = -3 and p = 5

(p - 5) ( p+3) = 0

p ( p +3 ) -5 ( p+3) = 0

p ^2 +3p -5p - 15 = 0

p ^2 -2p -15 = 0

Answer 2

• $\small\sf{(p\:-\:5)\:(p\:+\:3)\:=0}$

${ }$

${ }$

${:\:\:\Longrightarrow}\:\small\sf{(p\:-\:5)\:(p\:+\:3)\:=0}$

${ }$

${:\:\:\Longrightarrow}\:\small\sf{p}^{2}\:\sf{+\:3p\:-\:5p\:-\:15\:=\:0}$

${ }$

${:\:\:\Longrightarrow}\:\small\sf{p}^{2}\:\sf{-\:(5\:-\:3)\:p\:-\:15\:=\:0}$

${ }$

${:\:\:\Longrightarrow}\:\small\sf{p}^{2}\:\sf{-\:5p\:+\:3p\:-\:15\:=\:0}$

${ }$

${:\:\:\Longrightarrow}\:\small\sf{(p\:-\:5)\:+\:3\:(p\:-\:5)\:=\:0}$

${ }$

${:\:\:\Longrightarrow}\:\small\sf{p\:+\:3\:=\:0\:;\:p\:-\:5\:=\:0}$

${ }$

${:\:\:\Longrightarrow}\:\small\sf{p\:=\:-\:3\:;\:p\:=\:5}$

${ }$

${:\:\:\Longrightarrow}\:\small\sf{\underline{\boxed{\sf{\bold{p\:=\:-3,\:5}}}}}★$