Question

P = 500 R = 31/2% T = 146 days sovle the problem

Answer 1

Answer:

P = 500

R = 31/2%

T = 146 days = 146/365 yrs.

SI = P×R×T/100

= 500×31×146/100×100×365×2

= 2263000/146000

= 15.5. ans.....

A = P+SI

= 500+15.5

= 515.5. ANS......

Answer 2

We have,

• To find the Amount & Simple Interest when the following Principal is lent at certain (provided) rate of interest for particular time.

Given :

• Principal = Rs. 500
• Rate = 31/2 % p.a
• Time = 146 days

☛¤ To Find : Amount & SI

$\underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:}$

$\huge \bf{SOLUTION :}$

We know,

• Simple Interest= $\small \rm \frac{Principal \times Rate \times Time}{100}$
• Amount = $\small \rm Principal + \frac{Principal \times Rate \times Time}{100}$

$\small \sf\cancel{NOTE} : \text{ The time should be in \underline{years} always.}$

But,

• Time is in days (here),

$\therefore \: \: \text{Time in years} = \frac{ \textsf{Number of days}}{ \bf365} \\ \\ \tt{ \: \: \: \: \: \: \implies \frac{146}{365} \: \: \: yrs}$

Thus, Putting the values in the formula & performing calculations, we get,

$\bf{Amount = 500 + \frac{500 \times \frac{31}{2} \times \frac{146}{365} }{100} } \\ \\ \tt \: \: \implies500 + \frac{500 \times 31 \times \frac{146}{365} }{2 \times100} \\ \\ \tt\: \: \implies500 + \frac{500 \times 31 \times 146}{365 \times 100 \times 2} \\ \\ \tt \: \: \implies500 + \frac{ 500 \times 4526}{73000} \\ \\ \tt \: \: \implies500 + \frac{2263000}{73000} \\ \\ \tt \: \: \implies \frac{36500000 +2263000 }{73000} \\ \\ \tt \: \: \implies \frac{38763000}{73000} = 531$

Hence,

• Amount = Rs. 531
• Simple Interest = Rs. 31