p= (50y^2)^3÷81x^3 then prove that logp+3logx-6logy=6-3log2-4log3
Answers
Answered by
2
Answer:
195312500
Step-by-step explanation:
(50^2)^3÷81z^3
50^2×3 ÷81x3
50^6 ÷ 81x^3
1562500000 ÷ 81x^3
x^3 = 1562500000/8
x^3 = 195312500
Similar questions