p(5p²-80)/5p(p+4)
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Answers
Answered by
3
Step-by-step explanation:
Answer
(5p
2
−25p+20)÷5(p−4)
⇒5p
2
−25p+20=5(p
2
−5p+4)
=5[p
2
−4p−p+4]
=5[p(p−1)−4(p−1)]
=5[(p−1)(p−4)]
∴ (5p
2
−25p+20)÷(p−1)=
(p−1)
5(p−1)(p−4)
=5(p−4).
∴(5p
2
−25p+20)÷(p−1)=5(p−4).
Answered by
0
Hey mate,
p(5p²-80)/5p(p+4)
( − 25p + 20 ) ÷ 5 (p−4)
⇒ - 25p + 20 = 5( - 25p + 20 ) ÷ ( p - 1 =
=5(p−4).
∴ (5p 2 −25p+20)÷(p−1)=5(p−4).
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(5p2−25p+20)÷5(p−4)
⇒5p2−25p+20=5(p2−5p+4)
=5[p2−4p−p+4]
=5[p(p−1)−4(p−1)]
=5[(p−1)(p−4)]
∴ (5p2−25p+20)÷(p−1)=(p−1)5(p−1)(p−4)
=5(p−4).
∴(5p2−25p+20)÷(p−1)=5(p−4).