Math, asked by poojaishere, 5 months ago

p(5p²-80)/5p(p+4)
pls​

Answers

Answered by Anonymous
3

Step-by-step explanation:

Answer

(5p

2

−25p+20)÷5(p−4)

⇒5p

2

−25p+20=5(p

2

−5p+4)

=5[p

2

−4p−p+4]

=5[p(p−1)−4(p−1)]

=5[(p−1)(p−4)]

∴ (5p

2

−25p+20)÷(p−1)=

(p−1)

5(p−1)(p−4)

=5(p−4).

∴(5p

2

−25p+20)÷(p−1)=5(p−4).


Anonymous: Answer

(5p2−25p+20)÷5(p−4)

⇒5p2−25p+20=5(p2−5p+4)

=5[p2−4p−p+4]

=5[p(p−1)−4(p−1)]

=5[(p−1)(p−4)]

∴ (5p2−25p+20)÷(p−1)=(p−1)5(p−1)(p−4)​

=5(p−4).

∴(5p2−25p+20)÷(p−1)=5(p−4).
Answered by s1266aakansha782696
0

Hey mate,

\huge \fbox \orange{❥Question}

p(5p²-80)/5p(p+4)

\sf \purple{ \fbox{ \underline{★Answer★}}}

(  5p {}^{2} \\ − 25p + 20 ) ÷ 5 (p−4)

 5p {}^{2} \\ - 25p + 20 = 5(  p {}^{2} - 5p + 4 )</p><p></p><p>=5[p(p−1)−4(p−1)] </p><p></p><p>=5[(p−1)(p−4)]</p><p></p><p>∴ ( [tex] 5p {}^{2} \\ - 25p + 20 ) ÷ ( p - 1 =

{\tt{\purple{\underbrace{\bold{\huge{\frac{ 5 ( p - 1 ) ( p - 4 }{ ( p - 1 ) }}}}}}} =5(p−4).

∴ (5p 2 −25p+20)÷(p−1)=5(p−4).

Solution Also Available in Photo.

( Itz ❤Aakanksha❤ here! ) {}^{} \\

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