Question

(p-6)(p-4)(p+1)(p+3)+13 =?​

Answer 1

Answer:

p^4+18p^3-37p^2+66p+85

Step-by-step explanation:

= (p-6)(p-4)(p+1)(p+3)+13

= (p^2-4p-6p+24)(p^2+3p+p+3)+13

= (p^2-10p+24)(p^2+4p+3)+13

= p^4+4p^3+3p^2-10p^3-40p^2-30p+24p^3+96p+ 72+13

= p^4+18p^3-37p^2+66p+85