Math, asked by kishujha10, 10 days ago

P=6250 R=20% per year T=3.25 years
Find the compound interest ​

Answers

Answered by mathdude500
8

Answer:

\qquad\qquad\qquad\boxed{ \sf{ \: { \bf{ \:CI = 6170 \: }} \: }} \\  \\

Step-by-step explanation:

Given that,

Principal, P = 6250

Rate of interest, r = 20 % per annum

Time period, n = 3.25 years = 3 \frac{1}{4} years

We know,

Compound interest (CI) received on a certain sum of money of P invested at the rate of r % per annum compounded annually for n  \frac{m}{s}years is

\boxed{ \sf{ \:CI = P {\bigg[ 1 + \dfrac{r}{100} \bigg]}^{n} \bigg[ 1 + \dfrac{r}{100}  \times \dfrac{m}{s} \bigg] - P \: }} \\  \\

So, on substituting the values, we get

{ \sf{ \:CI = 6250 {\bigg[ 1 + \dfrac{20}{100} \bigg]}^{3} \bigg[ 1 + \dfrac{20}{100}  \times \dfrac{3}{4} \bigg] - 6250 \: }} \\  \\

{ \sf{ \:CI = 6250 {\bigg[ 1 + \dfrac{1}{5} \bigg]}^{3} \bigg[ 1 + \dfrac{1}{5}  \times \dfrac{3}{4} \bigg] - 6250 \: }} \\  \\

{ \sf{ \:CI = 6250 {\bigg[\dfrac{5 + 1}{5} \bigg]}^{3} \bigg[ 1 + \dfrac{3}{20}   \bigg] - 6250 \: }} \\  \\

{ \sf{ \:CI = 6250 {\bigg[\dfrac{6}{5} \bigg]}^{3} \bigg[\dfrac{20 + 3}{20}   \bigg] - 6250 \: }} \\  \\

{ \sf{ \:CI = 6250 {\bigg[\dfrac{216}{125} \bigg]}^{} \bigg[\dfrac{23}{20}   \bigg] - 6250 \: }} \\  \\

{ \sf{ \:CI = 50 {\bigg[\dfrac{216}{1} \bigg]}^{} \bigg[\dfrac{23}{20}   \bigg] - 6250 \: }} \\  \\

{ \sf{ \:CI = 5 (216)\bigg[\dfrac{23}{2}   \bigg] - 6250 \: }} \\  \\

{ \sf{ \:CI = 5 (108)(23) - 6250 \: }} \\  \\

{ \sf{ \:CI = 12420 - 6250 \: }} \\  \\

\sf\implies { \bf{ \:CI = 6170 \: }} \\  \\

\rule{190pt}{2pt}

Additional information :-

1. Amount received on a certain sum of money of Rs P invested at the rate of r % per annum compounded annually for n years is given by

\boxed{ \rm{ \:Amount \:  =  \: P \:  {\bigg[1 + \dfrac{r}{100} \bigg]}^{n} \:  \: }} \\

2. Amount received on a certain sum of money of Rs P invested at the rate of r % per annum compounded semi - annually for n years is given by

\boxed{ \rm{ \:Amount \:  =  \: P \:  {\bigg[1 + \dfrac{r}{200} \bigg]}^{2n} \:  \: }} \\

3. Amount received on a certain sum of money of Rs P invested at the rate of r % per annum compounded quarterly for n years is given by

\boxed{ \rm{ \:Amount \:  =  \: P \:  {\bigg[1 + \dfrac{r}{400} \bigg]}^{4n} \:  \: }} \\

4. Amount received on a certain sum of money of Rs P invested at the rate of r % per annum compounded monthly for n years is given by

\boxed{ \rm{ \:Amount \:  =  \: P \:  {\bigg[1 + \dfrac{r}{1200} \bigg]}^{12n} \:  \: }} \\

Answered by bharathijmay96
2

how to convert t-3.25years

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