Question

P = 65,000, T =1 3/4 years, R = 8.25% p.a. find the amount please send pic of answer​

Answer 1

︎︎︎ Before solving this sum we must have the following information:-

• Principal or sum(P): The money borrowed from an agency or an individual for a certain period of

time is called the principal or sum.

• Amount(A): The principal together with the interest is called the amount, Le, Amount (4) Principal (P+ Interest (1) Rate of interest: The interest on 100 per annum is called the rate of interest per annum

• Simple Interest(S.I): If the principal remains the same for the entire loan period, then the interest paid

is called the simple interest.

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Given:

$\sf{P = 65,000}$

$\sf{T=1\frac{3}{4}years}=\frac{7}{4}years$

$\sf{R = 8.25\% \: per \: annum}$

To find:

• The amount

Solution:

• At first we have to find the simple interest

• We know that,

$\sf{S.I= \frac{P \times R \times T}{100} }$

$\sf{=\frac{650{\cancel{00}} \times 8.25 \times \frac{7}{4} }{1{\cancel{00}}}}$

$\sf{=\frac { \cancel{{650}}\times{ \cancel{825}} \times 7}{ \cancel{4}×{\cancel{100}}} }$

$\sf{ = 9384.37}$

$\sf{\therefore \: {S.I\: =9384.37}}$

So,

$\sf{Amount = P + S.I}$

$\sf{ = 65000 + 9384.37}$

$\sf{ =74384.37}$

Hence, required amount is 74384.37

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★ Some formulas:

R = = (S.I x 100)/(P x T)

P = (S.I x 100)/(R x T)

T = (S.I x 100)/(P x R)

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