Question

P=6500. R=10%. N=2 find. A and CI​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$A = P( {1 + \frac{R}{100})}^{N} \\ = 6500 {(1 + \frac{10}{100 } )}^{2} \\ = 6500 {(1 + 0.1)}^{2} \\ = 6500 {(1.1)}^{2} \\ = 6500 \times 1.21 \\ \large{ \boxed{ \bf{A = { \underline{ \underline{₹ \: 7865}}}}}} \\ \\ C \: I = A - P \\ = 7865 - 6500 \\ \large{ \boxed{ \bf{C \: I = { \underline{ \underline{₹ \: 1365}}}}}}$