Question

-p + [6p - {q- (3p - 2q)}]​

Answer 1

Answer:

$-p+\left(6p-\left(q-\left(3p-2q\right)\right)\right)=8p-3q$

Step-by-step explanation:

$-p+\left(6p-\left(q-\left(3p-2q\right)\right)\right)$

$\gray{\mathrm{Remove\:parentheses}:\quad \left(a\right)=a}$

$=-p+6p-\left(q-\left(3p-2q\right)\right)$

$\gray{\mathrm{Expand}\:q-\left(3p-2q\right):\quad 3q-3p}$

$=-p+6p-\left(3q-3p\right)$

$\gray{-\left(3q-3p\right):\quad -3q+3p}$

$=-p+6p-3q+3p$

$\gray{\mathrm{Simplify}\:-p+6p-3q+3p:}$

$-p+6p-3q+3p$

$\gray{\mathrm{Group\:like\:terms}}$

$=-p+6p+3p-3q$

$\gray{\mathrm{Add\:similar\:elements:}\:-p+6p+3p=8p}$

$=8p-3q$