Question

p=8 h=10 find b using Pythagoras theorm

Answer 1

Hope this helps you ;)

Given:

Perpendicular is 8 units

Hypotenuse is 10 units

To find:

lenght of the base

Solution:

Using pythagoras theorem,

${p}^{2} + {b}^{2} = {h}^{2}$

${8}^{2} + {b}^{2} = {10}^{2}$

${b}^{2} = 100 - 64$

$b = \sqrt{36}$

$b = 6 units$

Answer 2

Answer:

According to Pythagoras theorem:

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

⇒(10)^2=(8)^2+(Base)^2

⇒100=64+(Base)^2

⇒(Base)^2=100-64=36

⇒Base=6